Verified Answer :
⁷/₁₀ kg
Further explanation
Given:
- Tiffany bought \(\frac{2}{5} \ kg\) of cherries.
- Linda bought \(\frac{1}{10} \ kg\) of cherries less than Tiffany.
Question:
How many kilograms of cherries did they buy altogether?
The Process:
Since Linda bought \(\frac{1}{10} \ kg\) of cherries less than Tiffany, we subtract \(\frac{1}{10} \ kg\) from the \(\frac{2}{5} \ kg\) of cherries Tiffany bought.
The least common multiple (LCM) of 5 and 10 is 10.
\(\boxed{ \ \frac{2}{5} - \frac{1}{10} = ? \ }\)
\(\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) - \frac{1}{10} \ }\)
\(\boxed{ \ = \bigg( \frac{4}{10} \bigg) - \frac{1}{10} \ }\)
\(\boxed{ \ = \bigg( \frac{3}{10} \ }\)
Therefore, Linda bought \(\frac{3}{10} \ kg\) of cherries.
Let us find out how many kilograms of cherries did they buy altogether.
\(\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }\)
\(\boxed{ \ \frac{2}{5} + \frac{3}{10} = ? \ }\)
\(\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) + \frac{3}{10} \ }\)
\(\boxed{ \ = \bigg( \frac{4}{10} \bigg) + \frac{3}{10} \ }\)
\(\boxed{\boxed{ \ = \bigg( \frac{7}{10} \ }}\)
Thus, they bought \(\frac{7}{10} \ kg\) of cherries altogether.
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Using Diagram
\(\boxed{Tiffany's cherries: \frac{2}{5} = \frac{4}{10}}\)
\(Tiffany's cherries: \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\) or 4 of 10 units.
\(\boxed{Linda's cherries = \frac{1}{10}}\) less than Tiffany's, so we subtract 1 from 4 units of Tiffany's, that is \(\boxed{\circ}\boxed{\circ}\boxed{\circ}\)
\(\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }\)
\(\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ} + \boxed{\circ}\boxed{\circ}\boxed{\circ} = \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\)
Thus, the number of the two diagrams is 7 out of 10 units or \(\frac{7}{10} \ kg\) of cherries.
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Keywords: Tiffany, bought, 2/5, kg of cherries, Linda, 1/10, less than, how many, kilograms, they buy altogether, 3/10, 7/10, LCM