When a car screeches to a sudden stop to avoid hitting a dog, it slows down from 9.00 m/s to 0.00 m/s in 1.50 s. Find the average acceleration of the car.
The formula for acceleration is
\(a=\frac{\Delta v}{t}\)
where \(a=\) acceleration, \(\Delta v=\) change in velocity, and \(t=\) time
So we get
\(a=\frac{-9.00\ m/s}{1.50\ s}\)
\(\rightarrow a=-6.00\ m/s^{2}\)
Answer:
a = - 6 m/s/s
here negative sign shows that velocity is decreasing with time
Explanation:
As we know that average acceleration is given by
\(a_{avg} = \frac{v_f - v_i}{\Delta t}\)
here we will have
\(v_f\) = final speed = 0 m/s
\(v_i\) = initial speed = 9 m/s
\(\Delta t\) = time interval = 1.50 s
now from above equation we will have
\(a = \frac{0 - 9}{1.5}\)
\(a = - 6 m/s^2\)
so average acceleration will be -6 m/s/s