When a car screeches to a sudden stop to avoid hitting a dog, it slows down from 9.00 m/s to 0.00 m/s in 1.50 s. Find the average acceleration of the car.

Verified Answer :

The formula for acceleration is
\(a=\frac{\Delta v}{t}\)
where \(a=\) acceleration, \(\Delta v=\) change in velocity, and \(t=\) time

So we get
\(a=\frac{-9.00\ m/s}{1.50\ s}\)
\(\rightarrow a=-6.00\ m/s^{2}\)

Answer:

a = - 6 m/s/s

here negative sign shows that velocity is decreasing with time

Explanation:

As we know that average acceleration is given by

\(a_{avg} = \frac{v_f - v_i}{\Delta t}\)

here we will have

\(v_f\) = final speed = 0 m/s

\(v_i\) = initial speed = 9 m/s

\(\Delta t\) = time interval = 1.50 s

now from above equation we will have

\(a = \frac{0 - 9}{1.5}\)

\(a = - 6 m/s^2\)

so average acceleration will be -6 m/s/s