Let's make the first even integer m and the second even integer n. The square of the first, decreased by the second is 130 is:
\(m^{2}\)-n=130 ---> Add n to each side
\(m^{2}\)=130+n ---> Take the square root of each side
m=±\(\sqrt{130+n}\)
Let's look at the first square number above 130, which is \(12^{2}\). m is 12, therefore the next consecutive even integer is 14.
\(12^{2}\)=144
144-14=130
The two consecutive integers are 12 and 14
