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A 2300 Kg car accelerates from rest to 6.00 m/s in 12.00 seconds. What is the net force acting in the car?

Verified Answer :

f=ma
a=(v2-v1)/(t2-t1)
a=(6-0)/(12-0)
a=6/12
a= .5 m/s^2
f=2300kg*.5m/s^2
f=1150N
f=1200N if using correct sig figs

AL2006

The car's acceleration is      (6 m/s) / (12 sec)  =  0.5 m/s² .

           Force = (mass) x (acceleration)

                     =  (2,300 kg) x (0.5 m/s²)

                     =    1,150 Newtons

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