Help find vertex: y=x^2+3x-4
( -3/2 , -25/4 ) is that what you need? Or?
y=x^2+3x-4a=1b=3c=4A of sym= negative b over 2a so the axis of symmetry would be 3/2 plug that into the original equation that's how you find the vertexy=(3/2)^2+3(3/2)-40.75+4.5-4Vertex= (3/2, 1.25)
