Haley substituted the values of a, b, and c into the quadratic formula below.
Haley substituted the values of a, b, and c into the quadratic formula below.
The quadratic formula is x equals negative b plus or minus the square root of b squared minus four times a times c, all over 2a.
Looking at the equation, we can find the values for a, b, and c
a=7
b= -10
c= -2
So then putting that back into standard form, which is ax^2+bx+c, we know Haley's function in standard form is 7x^2-10x-2
The required quadratic function will be 7x^2 -10x + 2 = 0
The standard quadratic equation is given as
ax^2 + bx + c = 0
where b and c are the coefficients used in finding the zeros of the equation
The general formula
x = -b±√b²-4ac/2a
Given the equation
x = -(-10)±√(-10)²-4(7)(-2)/2(7)
Comapring, we will have:
a = 7, b = -10 and c = 2
The required quadratic function will be 7x^2 -10x + 2 = 0
Learn more on quadratic equastion here: https://brainly.com/question/1214333