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When 1 mole of tin IV oxide is heated with 2 moles of hydrogen gas, 1 mole of tin metal and 2 moles of water vapor are generated. SnO2 + 2H2 → Sn + 2H2O How many moles of tin metal will be produced when 0.74 moles of tin IV oxide is heated?

Verified Answer :

Strahin90

1 of sno2 : 1 of sn = 0.74 of sno2 : x of sn, this is the proportion you need.
so
x is for mol of tin

x = 0.74 mol

Answer : The moles of tin metal produced will be, 0.74 mole

Explanation : Given,

Moles of \(SnO_2\) = 0.74 mole

The given balanced chemical reaction is,

\(SnO_2+2H_2\rightarrow Sn+2H_2O\)

From the balanced chemical reaction, we conclude that

As, 1 mole of \(SnO_2\) react to give 1 mole of Sn

So, 0.74 mole of \(SnO_2\) react to give 0.74 mole of Sn

Therefore, the moles of tin metal produced will be, 0.74 mole

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