A soccer player kicks a soccer ball at +10.0 m/s at an angle of 60°. What are the horizontal and vertical components of velocity of the kick?

This seems like a calculus problem. I'm assuming you would use cos and sin. so here's the vertical component +10.0m/s multiplied by sin60 = 8.66 rounded to the hundreths place. Now for horizontal, that would be +10.0m/s multiplied by cos60 = 5. hope this helped.

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rocioo rocioo · Answer 2 · 2019-12-20T12:43:20-05:00

Answer:

Horizontal component: \(V_{x}=+5m/s\)

Vertical component: \(V_{y}=+8.66m/s\)

Explanation:

We have the launch speed \(V =+ 10m/s\) and the angle of 60°, so the components of the speed \(V_{x}\) and \(V_{y}\) are those shown in the attached image.

\(V_{x}\) which is the horizontal component of the velocity can be found by multiplying the cosine of the angle by the initial velocity:

\(V_{x}=+10m/s(cos60)\\V_{x}=+10m/s(0.5)\\V_{x}=+5m/s\)

\(V_{y}\) which is the verticalcomponent of the velocity is found by multiplying the sine of angle by the initial velocity

\(V_{y}=+10m/s(sin60)\\V_{y}=+10m/s(0.866)\\V_{y}=+8.66m/s\)

In summary:

Horizontal component: \(V_{x}=+5m/s\)

Vertical component: \(V_{y}=+8.66m/s\)