Help on a question geometry
\(D:x-12>0\\ D:x>12\\ \log_3(x-12)=\log_35+2\log_33\\ \log_3(x-12)=\log_35+\log_33^2\\ \log_3(x-12)=\log_35+\log_39\\ \log_3(x-12)=\log_3(9\cdot5)\\ \log_3(x-12)=\log_345\\ x-12=45\\ \boxed{x=57}\)
2log 3 = log 3^2 = log 9 ;log 5 + 2log 3 = log 5 + log 9 = log( 5 * 9 ) = log 45 ;log ( x - 12 ) = log 45;x - 12 = 45 ;x = 12 + 45 ;x = 57 ;But, x - 12 > 0;And, 57 - 12 > 0 ;The solution is 57 .
