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Law of cosines: a2 = b2 + c2 – 2bccos(A)


Which equation correctly uses the law of cosines to solve for y?

92 = y2 + 192 – 2(y)(19)cos(41°)

y2 = 92 + 192 – 2(y)(19)cos(41°)

92 = y2 + 192 – 2(9)(19)cos(41°)

y2 = 92 + 192 – 2(9)(19)cos(41°)

Law of cosines: a2 = b2 + c2 2bccos(A) Which equation correctly uses the law of cosines to solve for y? 92 = y2 + 192 2(y)(19)cos(41 ) y2 = 92 + 192 2(y)(19)cos class=

Verified Answer :

In this case,
a = y
b = 9
c = 19
So...
\(a^2 = b^2 + c^2 - 2bc*\cos(A)\)
\(y^2 = 9^2 + 19^2 - 2*9*19*\cos(41^{\circ})\)
which means the answer is choice D

huntrw6

The correct answer is:

D. \(y^{2}=9^{2}+19^{2}-2(9)(19)cos(41)\)

\(|Huntrw6|\)

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