Answer:
The solution will not change.
Step-by-step explanation:
Let y > 2x + p and y < 2x + p,
Where, p is any constant,
∵ If we subtract any number on both sides of an equality, the sign of inequality does not change,
i.e. y - p > 2x and y - p < 2x
\(\implies \frac{y-p}{2} > x\text{ and }\frac{y-p}{2} < x\)
\(\implies x\in (-\infty, \frac{y-p}{2})\cap (\frac{y-p}{2}, \infty )-----(1)\)
Similarly, If the inequality is,
\(y < 2x + p\text{ and }y > 2x + p\)
\(\implies \frac{y-p}{2} < x\text{ and }\frac{y-p}{2} > x\)
\(\implies x\in (-\infty, \frac{y-p}{2})\cap (\frac{y-p}{2}, \infty )-----(2)\)
From equation (1) and (2),
It is clear that, the solution will not change after reversing the sign of inequality.
