lunafan031 lunafan031

05-12-2016
Mathematics

Answered

how do i write 12+(43-7)÷6 in order of operations

Verified Answer :

05-12-2016

Bidmas so 43-7 then divide by 6 then add 12

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Anonymous Anonymous

05-12-2016

using PEMDAS

P: parenthesis
E: exponents
M: multiplication
D: division
A: addition
S: subtraction

In this case 12+(43-7)÷6
you need to do parenthesis first (43-7)
then division, ÷6
then addition, 12+

12+(43-7) ÷ 6
= 12 + 36 ÷ 6
= 12 + 6
= 18

Answer Link

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