Answer:
The common difference is \(11\)
Step-by-step explanation:
we know that
In an Arithmetic Sequence the difference between consecutive terms is a constant called the common difference
so
In this problem we have
\(-15,-4,7,18,29,...\)
Let
\(a1=-15\ a2=-4\ a3=7\ a4=18\ a5=29\)
Find the difference between consecutive terms
\(a5-a4=29-18=11\)
\(a4-a3=18-7=11\)
\(a3-a2=7-(-4)=11\)
\(a2-a1=-4-(-15)=11\)
therefore
The sequence is an Arithmetic Sequence
The common difference is \(11\)
