How do I factor 5x^2-14x+8=0 ?
5×^2 - 10× - 4× +8 =05x(x-2) - 4(×-2)=0(x-2)(5x-4)=0x = 2, 4/5
5x²-14x+8=0(5x - 4)(x - 2) = 0factor form is (5x-4)(x-2).If solve, the answer would bex = 4/5 , x = 2
