A sled is pushed along an ice covered lake. It has some initial velocity before coming to rest in 15m. It took 23 seconds before the sled and rider came to a rest. If the rider and sled have a combined mass of 52.5 kg, what is the magnitude and direction of the stopping force? What do we call the stopping force?

Since no external force is acting except frictional force, so stopping force is frictional force with magnitude ~ 3N in the direction opposite to the motion of sledge.

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Histrionicus Histrionicus · Answer 2 · 2021-12-02T02:26:27-05:00

A sled is pushed along an ice-covered lake. It has some initial velocity before coming to rest in 15m. It took 23 seconds before the sled and rider came to a rest. If the rider and sled have a combined mass of 52.5 kg, the magnitude, and direction of the force - 2.98 N which is called friction.

Given:

Time t = 15 s

distance d = 23 m

mass = 52.5

As we know the formula,

\(Solution:\\\\\\bar v = \frac{d}{t}\\\\ = \frac{15}{23}\\ \\ = 0.65 \ m/s\\\\According\ to\ the\ question,\\v_f =0\\then,\\2 \bar v = v_i\\2(0.65)=v_i\\v_i=1.3 \ m/s\\u = Initial\ velocity,\\v = Final\ Velocity,\\a = acceleration\\\\According\ to\ the\ second\ law\ of\ motion\\Force = m\times a\\ = (-.057)\times 52.5\\ = -2.97 \ N\)

Thus, F is taken to be negative. So, the stopping force is -2.97 N and this force is the frictional force and its direction is opposite to that of motion.

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