Which equation represents the line that passes through (–6, 7) and (–3, 6)?
Answer:
Equation of line become \(y= \frac{- 1 *x}{3}+ 5\).
Step-by-step explanation:
slope of the line
we know that the formula to calculate the slope between two points is equal to
Slope (m) = \(\frac{y_{2}- y_{1} }{x_{2}-x_{1}}\).
substitute the values
(m) = \(\frac{6 - 7} }{ -3 - (-6)}\).
(m) = \(\frac{-1} }{3}\).
With the slope m and the point (-6, 7) find the equation of the line
we know that
the equation of the line in the point-slope form is equal to
\((y - y_{1}) = m ( x - x_{1})\).
substitute the values
\((y - 7) = \frac{-1}{3} (x - ( -6))\).
\((y - 7) = \frac{-1}{3} (x + 6)\).
\((y - 7) = \frac{-x}{3} +2 )\).
On adding both sides by 7.
\(y= \frac{-x}{3} - 2 + 7\).
\(y= \frac{-x}{3}+ 5\).
Therefore, equation of line become \(y= \frac{-1 *x}{3}+ 5\).