(k^3-8k^2+16k-5)÷(k-5)
Start by factoring the numerator. We know that \((k-5)\) is a factor. So, your answer becomes:
\((k -5)(k^2-3k+1) / (k-5)\)
Now we have two of the same terms \((k-5)\) in the numerator and the denominator, we cancel them out and are left with:
\(k^2-3k+1\)
(Kx3-16k^ + 16k-5):(k-5)
(3k-16k^+16k-5):(k-5)
(19k-16k^-5):(k-5)
19-16k^-5
K-5
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