The correct answer is option a. 25%.
We need to find out the brown colored cats with long tail.
So, the genotype of the individual must have atleast one B allele and ss allele.
From the punette square given above
The number of offspring having Bbss or Bsbs is 4.
Total number of the offspring is 16.
So, the probability of the brown cat with a long tail is \(\frac{4}{16} =\frac{1}{4}\) =25%.
Hence, the brown cat with a long tail are 25% of the total population
