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Verified Answer :

Assuming that's log base 10, the inverse would be k(x) = 10^x

h(k(x)) = x
and
k(h(x)) = x

apologiabiology

to solve
replace h(x) with y
switch x and y
solve for y
replace y with h⁻¹(x)

remember that
logx is base 10
and that
\(log_xy=b\) means \(x^b=y\)
so


y=log(x)
x=log(y)
convert, assume base 10
\(10^x=y\)
ha! that's already solved for y
\(y=10^x\)
\(h^{-1}(x)=10^x\)

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