16x² + 1 = 8x First, make this a quadratic equation. Subtract 8x from both sides
16x² -8x + 1 = 0 Now, since ax² + bx + c = 0 is quadratic equation form, a = 16, b = -8, and c = 1. Plug those into the quadratic formula.
x = \(\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}\) Plug in your numbers
x = \(\frac{-(-8) \pm \sqrt{(-8)^2 - 4(16)(1)} }{2(16)}\) Simplify the double negative (- (-8))
x = \(\frac{8 \pm \sqrt{(-8)^2 - 4(16)(1)} }{2(16)}\) Simplify (-8)²
x = \(\frac{8 \pm \sqrt{64 - 4(16)(1)} }{2(16)}\) Simplify 4(16)(1)
x = \(\frac{8 \pm \sqrt{64 - 64} }{2(16)}\) Subtract 64 from 64
x = \(\frac{8 \pm \sqrt{0} }{2(16)}\) Mutiply 2 and 16
x = \(\frac{8 \pm \sqrt{0} }{32}\) Get rid of the \(\sqrt{0}\)
x = \(\frac{8}{32}\) Simplify
x = \(\frac{1}{4}\)
