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Verified Answer :

Let z be any number (like x would be)

if we set z equal to 2x-6y, then we get z = 2x-6y

The system 

2x-6y = 8
2x-6 = 3

turns into this new system

z = 8
z = 3

but z is a single number. It can't be both 8 and 3 at the same time. So there are no solutions

prettyoddmay

The answer is no solution. If you use elimination, by subtracting the second equation from the first, you come out with 0=5, which is a false statement. Therefore, there is no solution.