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which of the following is a correct equation for the line passing through the point (-3,2) and having slope m=2/3.

Check all that apply.

A.) y-2=2/3(x+3)
B.) 2x-3y=-12
C.) y=2/3x+4
D.) y=2/3x

Verified Answer :

kshaffer

y-2=2/3(x+3)
2x-3y=-12
y=2/3x+4

Answer:

Step-by-step explanation:

Given : \((x_1,y_1)=(-3,2)\)

          \(m=\frac{2}{3}\)

Solution:

Equation of line:\(y-y_1 = m(x-x_1)\)

Substituting the given values

⇒\(y-2= \frac{2}{3}(x-[-3])\)

⇒\(y-2= \frac{2}{3}(x+3)\)  --A

⇒ \(3y-6= 2x+6\)

⇒ \(2x-3y = -6-6\)

⇒\(2x-3y =-12\)   ---B

⇒\(2x+12 =3y\)

⇒ \(\frac{2x+12}{3} =y\)

⇒ \(\frac{2}{3}x+4 =y\) ---C

Hence Equation A ,B and C are the correct equations

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