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Verified Answer :

sub (x+1) for x

f(x+1)=2(x+1)^2+3
f(x+1)=2(x^2+2x+1)+3
f(x+1)=2x^2+4x+2+3
f(x+1)=2x^2+4x+5

D is answer

Answer:

option (d) is correct.

\(f(x+1) = 2x^2+4x+5\)

Step-by-step explanation:

Given : \(f(x) = 2x^2 + 3\)

We have to choose out of given option which represent f(x + 1)

Consider the given function \(f(x) = 2x^2 + 3\)

Since we have to find f( x + 1 ) , replace x by x + 1 in the given function f(x) , we have,

\(f(x+1) = 2(x+1)^2+3\)

Using algebraic identity, \((a+b)^2=a^2+b^2+2ab\) , we have,

\(f(x+1) = 2(x^2+1+2x)+3\)

Simplify the expression by multiplying 2 with each term in bracket, we have,

\(f(x+1) = 2x^2+2+4x+ 3\)

Simplify , we have,

\(f(x+1) = 2x^2+4x+5\)

Thus, option (d) is correct.