log4 (x+4) = 1 ?

I assume you distribute log base of four to (x+4). But I don't know how to go about it, please help!!

Log rule: \(\log_a(b)=x\leftrightarrow a^x=b\)
By that rule, \(\log_4(x+4)=1\leftrightarrow 4^1=x+4\)
We know that \(4^1=4\) so we now have \(4=x+4\)
Subtract 4 from both sides and you get x=0.

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apologiabiology apologiabiology · Answer 2 · 2016-12-01T23:39:02-05:00

apologiabiology apologiabiology

01-12-2016

remember
\(log_ab=c\) means \(a^c=b\)
so

\(log_4(x+4)=1\) means \(4^1=x+4\)
4=x+4
minus 4 both sides
x=0

a fun tip is
if you get \(log_a(b)=1\), then a=b

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log4 (x+4) = 1 ? I assume you distribute log base of four to (x+4). But I don't know how to go about it, please help!!

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log4 (x+4) = 1 ?

I assume you distribute log base of four to (x+4). But I don't know how to go about it, please help!!