Katiecastro Katiecastro

01-12-2016
Mathematics

Answered

How do I find dy/dx of the equation 4x^3-3xy^2+y^3=28 at the point (3,4)?

Verified Answer :

MissPhiladelphia MissPhiladelphia

12-12-2016

To get the dy/ dx of the equation 4x^3-3xy^2+y^3=28 at the point (3,4), get the
first derivative then substitute the given value.

Y = 4x^3-3xy^2+y^3=28

Dy / dx = (2x / y) + 1

Substitute the given

Dy /dx = ( (2*3)/ 4) + 1

Dy/dx = 5/2

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