Answer:
\(144.9\leq x\leq 145.5\)
Step-by-step explanation:
Let x represent actual weight of object.
We have been that the weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 lbs.
\(|\text{Actual}-\text{Ideal}|\leq \text{Tolerance}\).
Upon substituting our given values, we will get:
\(|x-145.2|\leq 0.3\)
Applying absolute value rule \(|u|\leq a=-a\leq u\leq a\), we will get:
\(-0.3\leq x-145.2\leq 0.3\)
Add 145.2 on each side:
\(-0.3+145.2\leq x-145.2+145.2\leq 0.3+145.2\)
\(144.9\leq x\leq 145.5\)
Therefore, our required range will be \(144.9\leq x\leq 145.5\).
