Hn, well you should use the rule to answer this.. \(log_a(n)-log_a(m)=log_a (\frac{n}{m} )\)
Sorry if this doesn't seem to help, but here is the explanation:
\(log_2 (\frac{12b-21}{b^2-3} )=2\)
\(\frac{12b-21}{b^2-3} =4\)
\(12b-21=4(b^4-3)\)
\(0=4b^2-12b-12+21\)
\(0=4b^2-12b+9\)
\(0=4b^2-6b-6b+9\)
\(0=2b(2b-3)-3(2b-3)\)
\(0=(2b-3)(2b-3)\)
\(b= \frac{3}{2}\)
Hn, so from this information we can determine that this solution does not work. And so forth your solution set shall indeed be: {x= 0}
I wish you good luck on your homework and hopefully I was somewhat beneficial to your needs.
Best regards~ Sans
