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At 9:00 A.M. It was -8º F. At 3:00 P.M. the temperature was 10º F.


Which expression shows how to find the average increase per hour in temperature?




[10−(-8)]÷6




[10+(-8)]÷6



6÷(−8+10)



6÷[−8−(−10)]

Verified Answer :

increase per hour=increase/hours

increase=temp(final)-temp(initial)
hours=9am to 3pm
given

temp(initial)=-8
temp(final)=10

increase=10-(-8)
increase=10+8
increase=18

how many hours elapsed
9 to 12 is 3 hours
12 to 3 is 3
3+3=6
6 hours elapsed
increase per hour=18/6=3f/h

oh, you want the equation

[10-(-8)]/6 is the equation
the first one