A laboratory technician needs to make a 72-liter batch of a 20% acid solution. How can the laboratory technician combine a batch of an acid solution that is pure acid with another that is 10% to get the desired concentration?
Answer: 8 L of 100% pure acid and 64 L of 10% acid must be combined
Step-by-step explanation:
According to the dilution law,
\(C_1V_1+C_2V_2=C_3V_3\)
where,
\(C_1\) = concentration of pure acid solution = 100 %
\(V_1\) = volume of pure acid solution = x L
\(C_2\) = concentration of another acid solution= 10%
\(V_2\) = volume of another acid solution= (72-x) L
\(C_3\) = concentration of resulting acid solution = 20 %
\(V_1\) = volume of resulting acid solution = 72 L
Putting the values in the equation:
\(100\times x+10\times (72-x)=20\times 72\)
\(x=8L\)
Therefore, the laboratory technician must take 8 L of 100% pure acid and (72-8) = 64 L of 10% acid to get 72-liter batch of a 20% acid solution.