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what is the approximate percent increase when the population of a town increases from 12089 to 15025? round the amounts to the nearest ten thousand.

Verified Answer :

bartdrinksmalk

The rate of increase is
\(\frac{15025}{12089}\approx1.242865\)

The percent of increase is then
\((1.242865-1)*100\%=0.242865*100\%=24.2865\%\)

bcalle

15025-12089 = 2936
2936/12089 = .2429
.2429 * 100 = 24.29% or Approx 24 %

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