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Verified Answer :

For small deflections, T = 2pisqrt(L / g) where T is period, L is length and g is gravity.

Setting the equations to the same period, 2pisqrt(3.85 / g) = 2pi(L / (1/6 g))

The equation reduces to 3.85 m = 6 L so L = 0.642 m
chrsclrk ยท 7 years ago