Answer:
\(y=\frac{2}{3}x+9\)
Step-by-step explanation:
We can describe a line using the following equation :
\(y=ax+b\)
Where ''a'' and ''b'' are real numbers.
In the equation, the number ''a'' is the slope of the line. If we want a line with slope \(\frac{2}{3}\) ⇒
\(y=\frac{2}{3}x+b\)
The intersection of a line with the y-axis can be calculated replacing \(x=0\) in the equation ⇒
\(y=(\frac{2}{3}).(0)+b\\y=b\)
The interception is the real number ''b''. We want that interception to be 9
⇒
\(y=\frac{2}{3}x+9\) is the equation of the line with slope \(\frac{2}{3}\) and that intersects the y-axis at the point \((0,9)\)
