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Answer:

-3 is the best answer i hope it helps


Step-by-step explanation:


We have been given a polynomial function \(f(x)=x^3-x^2-9x+9\). We are asked to choose the root of the function from given choices.

Let us set our polynomial equal to 0.

\(x^3-x^2-9x+9=0\)

Now we will factor our polynomial by grouping method.

\((x^3-x^2)+(-9x+9)=0\)

Let us factor out greatest common factor from each group.

\(x^2(x-1)-9(x-1)=0\)

\((x-1)(x^2-9)=0\)

We can further factor \((x^2-9)\) using difference of squares.

\((x-1)(x^2-3^2)=0\)

\((x-1)(x+3)(x-3)=0\)

Using zero product property, we will get:

\((x-1)=0\text{ (or) }(x+3)=0\text{ (or) }(x-3)=0\)

\(x=1\text{ (or) }x=-3\text{ (or) }x=3\)

Upon looking at our given choices, we can see that \(-3\) is the correct choice, therefore, \(-3\) is root of the given polynomial.