what is the reasonable estimate of the average kinetic energy of an athlete during a 100m race that takes 10s ?
Given info is
Distance= 100m and Time=10s
Velocity=100/10=10m/s
Kinetic energy= 1/2mv^2
Rough estimate of mass of athlete=80kg
Ek= 1/2x80x10^2= 4000J
The Kinetic energy of the athlete will be 50 times of the mass of the athlete.
We have a athlete who completed a 100m race in 10 seconds.
We to estimate the average kinetic energy of the athlete.
The formula to calculate the kinetic energy of any moving body is -
K.E. = \(\frac{1}{2} mv^{2}\)
According to question -
Distance covered by athlete = 100 meters
Time taken by the athlete = 10 seconds
Let's assume the mass of the athlete = M Kg
Consider the formula for the Kinetic energy of the body -
K.E. = \(\frac{1}{2} mv^{2}\)
We know that -
v = \(\frac{distance}{time} = \frac{x}{t}\)
Substituting the value of velocity in equation of kinetic energy -
K.E = \(\frac{1}{2} m(\frac{x}{t}) ^{2}\)
We can see that the kinetic energy of the athlete is -
K.E. \(\alpha\; (\frac{x}{t})^{2}\)
Greater the square of the ratio of x and t, greater will be the kinetic energy.
K.E. = 0.5 x M x 10 x 10
K.E. = 50M
Hence, the Kinetic energy of the athlete will be 50 times of the mass of the athlete.
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