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C

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pierinagiusiano

Answer:

Option A.

Step-by-step explanation:

We have \(P(y)=y^3-9y^2+10y+5\) and (y-1) is a factor of P(y) if and only if P(1)=0, this means if:

y-1=0

y=1

Now we have to replace y=1 in \(P(y)=y^3-9y^2+10y+5\) this is:

\(P(1)=1^3-9.(1)^2+10.(1)+5\\P(1)=1-9+10+5\\P(1)=7 eq 0\)

Then \(P(1) eq 0\) this means that (y-1) isn't a factor of \(y^3-9y^2+10y+5\).

And the correct option is A.

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