factor completely:
4x^3 - 36x
You would take out a 4x out of both terms because this is a common factor 4x^3-36x4x(x^2-9) and then you would notice that (x^2-9) is a difference of squares, so that factors out too 4x(x-3)(x+3)that is all you can factor! hope this helps
the factor of this is 4x(x^2-9)then x^2-9 can be factored using sum and difference.4x(x+3)(x-3)
