Which of the following is the inverse function of y = 3x + 1?
x = 3y + 1
y = (1/3)x + 1/3
y = (x – 1)/3
y = x/3 - 1
x = 3y + 1
y = (1/3)x + 1/3
y = (x – 1)/3
y = x/3 - 1
