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A basketball player, who weighs 600 newtons, jump 0.5 meters vertically off the floor. Calculate her kinetic energy just before hitting the floor.

a)300J

b)3000J

c)9.81m/s^2

d)0

Verified Answer :

kilograms to newtons is 1 kilogram is 9.81 newtons, so if you divide that by 600? you get close to 0 so I think it's D

Lovelee22

Answer:

300 J

Explanation:

\(v = \sqrt{2gh}\)

\(KE = \frac{1}{2}mv^{2}\)

——

\(v = \sqrt{2(9.81 m/s^{2})(0.5 m)}\\ v = 3.13\)

\(KE = \frac{1}{2}(61.2 kg)(3.13 m/s)^{2}\\ KE = 300 J\)

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