A church has 8 bells in its bell tower. Before each church service 5 bells are rung in sequence. No bell is rung more than once. How many sequences are there?
Use the ! tool to find the # of combinations.
8!/5! = 40,320/120 = 336
Using permutations, there are 6720 sequences of ringing the church bell before the church service.
A permutation is a mathematical technique that determines the number of possible arrangements in a set when the order of the arrangements matters.
\(_{n} P_{r}=\frac{n !}{(n-r) !}\\\\_{8} P_{5} = \frac{8 !}{(8-5) !}\\\\_{8} P_{5} = 6720\)
Number of permutations of bells = 6720
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