How many moles of solute are contained in a 250.0 ml solution with a concentration of 2.5 M
molarity = no. of moles of solute / volume of solution in liters
2.5 = no. of moles of solute / 0.25
no. of moles of solute = 2.5 x 0.25 = 0.625 moles
Answer: 0.625 moles of solute are contained in a 250.0 ml solution with a concentration of 2.5 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
\(Molarity=\frac{n\times 1000}{V_s}\)
where,
n= moles of solute = ?
\(V_s\) = volume of solution in ml = 250 ml
Now put all the given values in the formula of molarity, we get
\(2.5M=\frac{n\times 1000}{250ml}\)
\(n=0.625moles\)
Therefore, the moles of solute will be 0.625.