Katarinche Katarinche

28-11-2016
Mathematics

Answered

2sinxcosx-sin(2x)cos(2x)=0

Agive the most general solutions to equation
Bsimplify the first expression using double angle identity for sine
Cfactor the left side of equatioin
Dsolve the factored equation

Verified Answer :

syed514 syed514

28-11-2016

2sinxcosx = sin(2x)
2sinxcosx-sin(2x)cos(2x)=0
sin(2x)-sin(2x)cos(2x)=0

now factor out sin(2x)
sin(2x)[1 - cos(2x)] = 0
sin(2x) = 0
since
sin(0) = 0
2x = 0
x = 0

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