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When 20.0 grams of a substance is completely melted at its melting point, 820 Joules are absorbed, what is the heat of fusion of this substance?

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mec01916

its Q=ML wher Q is energy in joules, M is the mass in kg AND L is the latent heat of fusion. the ans is 41000j/kg

Answer: Heat of fusion of this substance is 41 J/g

Explanation:

Latent heat of fusion is the amount of heat required to convert 1 g of solid to liquid at atmospheric pressure.

It is given that amount of heat required to melt 20 gram of a substance= 820 J

Heat required to melt 20 g of a substance= 820 J

Thus Heat required to melt 1 g of  a substance=\(\frac{820}{20}\times 1=41J\)

Thus heat of fusion of this substance is 41 J/g

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