Answer:
\(4x^2+5x-21\)
Step-by-step explanation:
We have been given the length an width of a rectangle. We are asked to find the area of the rectangle.
\((x+3)(4x-7)\)
Using FOIL, we will get:
\(x(4x-7)+3(4x-7)\)
\(4x^2-7x+12x-21\)
\(4x^2+5x-21\)
Therefore, the area of the rectangle would be \(4x^2+5x-21\).
