Answer : The number of moles of water formed can be, 128 moles
Solution : Given,
Moles of hydrogen gas = 138 moles
Moles of oxygen gas = 64 moles
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction will be,
\(2H_2+O_2\rightarrow 2H_2O\)
From the balanced reaction we conclude that,
As, 2 moles of hydrogen gas react with 1 mole of oxygen gas
So, 138 moles of hydrogen gas react with \(\frac{138}{2}=69\) moles of oxygen gas
But the given moles of oxygen gas is 64 moles.
That means oxygen gas is a limiting reagent and hydrogen gas is an excess reagent.
Now we have to calculate the moles of water.
From the reaction we conclude that,
As, 2 moles of oxygen react to give 1 mole of water
So, 64 moles of oxygen react to give \(64\times 2=128\) moles of water
Therefore, the number of moles of water formed can be, 128 moles
