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Verified Answer :

SOH, CAH, TOA

sin=oposite/hypotonuse
cos=adjacent/hyptonuse

sin60=CB/6, we want AC

cos60=AC/6
then times 6 both sides
6cos60=ac

answer is 6cos60

Answer:

Option B is correct.

Length of the bar AC i.e

\(AC = 6 \cos 60^{\circ}\)

Step-by-step explanation:

As per the statement:

In right angle triangle ACB

Side AB = 6 feet and \(\angle A = 60^{\circ}\)

We have to find the length of bar AC:

Using cosine function ratio:

\(\cos \theta = \frac{\text{Adjacent Side}}{\text{Hypotenuse side}}\)

Here,

Adjacent side= AC

Hypotenuse side = AB = 6 feet

\(\cos A = \frac{\text{AC}}{\text{AB}}\)

then;

substitute the given values we have;

\(\cos 60^{\circ} = \frac{\text{AC}}{6}\)

Multiply both sides by 6 we have;

\(AC = 6 \cos 60^{\circ}\)

Therefore, the length of the bar \(AC = 6 \cos 60^{\circ}\)