If it takes 526 J of energy to warm 7.40g of water by 17 degrees celsius, how much energy would be needed to warm 7.40g of water by 55 degrees celsius?
The energy needed to warm water be 55 Celsius would be
Q=mc Delta T
We are given the following data
Q=526
m=7.4
T=17C= 526/17*7.4
Putting in the equation we get
Q=mc DeltaT
Q=7.4x55x526/17x7.4
=55x526/17
=1701.64 C
Answer:
Heat required = 1702 J
Explanation:
The amount of heat energy (Q) required to raise the temperature of water of mass (m) is given as:
\(Q = mc\Delta T\)
where c = specific heat capacity
ΔT =change in temperature
It is given that:
When ΔT = 17 C, Q = 526 J and m = 7.40 g
i.e. \(526J = 7.40g*c*(17 C) \\\\c = 4.181 J/g C\)
The amount of heat required to increase the temperature of 7.40 g water by 55 C would be:
\(Q = 7.40 g*4.181J/gC*55C =1702 J\)