At Shaw's Market apples cost $10 per case and bananas cost $6 per case. If an order comes in for a total of 300 cases for $2,000, what was the specific number of cases of apples?
Answer:
50 was the specific number of cases of apples
Step-by-step explanation:
let x be the number of cases of apples and y be the number of cases of banana.
As per the statement:
At Shaw's Market apples cost $10 per case and bananas cost $6 per case
⇒Cost of x cases of apples = 10 x and Cost of y cases of apples = 6 y
If an order comes in for a total of 300 cases
⇒\(x+y = 300\) ....[1]
It is also given that total cost for the cases of apple and banana is, $2000
⇒\(10x +6y = 2000\) ....[2]
Multiply equation [1] by 6 both sides we get;
\(6x+6y = 1800\) .....[3]
Subtract [3] from [2] to get eliminate y:
\(10x+6y-6x-6y = 2000-1800\)
Combine like terms;
\(4x = 200\)
Divide both sides by 4 we get;
x = 50
Therefore, the number of cases of apples are: 50