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What is the factored form of x2 – 196?

(x – 14)2

(x + 14)2

(x – 28)(4x + 7)

(x – 14)(x + 14)


What is the factored form of 9x2 – 64?

(3x – 8)2

(3x + 8)2

(3x – 8)(3x + 8)

(9x – 8)(x + 8)


What is the factored form of 49x2 – 56x + 16?

(7x – 4)2

(7x + 4)(7x – 4)

(7x + 4)2

(7x – 8)2

Verified Answer :

Q1. The answer is (x – 14)(x + 14)

x² - 196 = x² - 14²

a² - b² = (a - b)(a + b)
a = x, b = 14

x² - 196 = x² - 14² = (x - 14)(x + 14)


Q2. The answer is (3x - 8)(3x + 8)

9x² - 64 = (3x)² - 8²

a² - b² = (a - b)(a + b)
a = 3x, b = 8

9x² - 64 = (3x)² - 8² = (3x - 8)(3x + 8)


Q3. The answer is (7x - 4)²

49x² - 56x + 16 = (7x)² - 2 7x 4 + 4²

(a - b)² = a² - 2ab + b²
a = 7x, b = 4

49x² - 56x + 16 = (7x)² - 2 7x 4 + 4² = (7x - 4)²

The factorized form of \({x^2}-196\) is \(\boxed{\left({x - 14}\right)\left({x + 14}\right)}\).

The factorized form of \(9{x^2}-64\) is \(\boxed{\left({3x - 8}\right)\left({3x + 8}\right)}\) .

The factorized form of \(49{x^2}-56x+16\) is \(\boxed{{{\left({7x - 4}\right)}^2}}\) .


Further explanation:

The formula of \({a^2}-{b^2}\) can be written as,

\(\boxed{{a^2}-{b^2}=\left({a + b}\right)\left({a - b}\right)}\)

The formula of \({a^2}-2ab+{b^2}\) can be written as,

\(\boxed{{a^2}-2ab+{b^2}={{\left({a - b}\right)}^2}}\)


Given:

The equations are as follows.

1. \({x^2}-196\)

2. \(9{x^2}-64\)

3. \(49{x^2}-56x+16\)


Explanation:

(1)

The factorized form of the equation \(P\left(x\right)={x^2}-196\) can be obtained by solving the equation using the formula \(\boxed{{a^2}-{b^2}=\left({a + b}\right)\left({a - b}\right)}\).

The factorized form of \({x^2}-196\) is \(\boxed{\left({x-14}\right)\left({x + 14}\right)}\).


(2)


The factorized form of the equation \(Q\left(x\right)=9{x^2}-64\) can be obtained by solving the equation using the formula \(\boxed{{a^2}-{b^2}=\left({a+b}\right)\left({a-b}\right)}\).

\(\begin{aligned}Q\left(x\right)&=9{x^2}-64\\&={\left({3x}\right)^2}-{\left(8\right)^2}\\&=\left({3x+8}\right)\left({3x-8}\right)\\\end{aligned}\)

The factorized form of \(9{x^2}-64\) is \(\boxed{\left({3x-8}\right)\left({3x+8}\right)}\).


(3)

The factorized form of the equation \(R\left(x\right)=49{x^2}-56x+16\) can be obtained by solving the equation using the formula \(\boxed{{a^2}-2ab+{b^2}={{\left({a-b}\right)}^2}}\).

\(\begin{aligned}R\left(x\right)&=49{x^2}-56x+16\\&={\left({7x}\right)^2}-2\left({7x}\right)\left(4\right)+{\left(4\right)^2}\\&={\left({7x+4}\right)^2}\\\end{aligned}\)

The factorized form of \(49{x^2}-56x+16\) is \(\boxed{{{\left({7x-4}\right)}^2}}\).


Learn more:

1. Learn more about inverse of the function https://brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function https://brainly.com/question/3412497


Answer details:

Grade: High School

Subject: Mathematics

Chapter: polynomials


Keywords: quadratic equation, equation factorization. Factorized form, polynomial, quadratic formula, zeroes