Answer: The specific heat of the metal is \(0.23J/g^0C\)
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
\(Q=m\times c\times \Delta T\)
Q = Heat absorbed=\(2.50kJ=2500J\)
m= mass of substance = 135 g
c = specific heat capacity = ?
Initial temperature = \(T_i\) = 19.5°C
Final temperature = \(T_f\) =100.0°C
Change in temperature ,\(\Delta T=T_f-T_i=(100-19.5)^0C=80.5^0C\)
Putting in the values, we get:
\(2500=135\times c\times 80.5^0C\)
\(c=0.23J/g^0C\)
The specific heat of the metal is \(0.23J/g^0C\)