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amandmccal234

the answer for the question that was asked is true

Correct answer is TRUE.

\(\tan \alpha= \frac{x}{y} \\ \\ \alpha=45^o \Rightarrow x=y \Rightarrow \frac{x}{y} =1\Rightarrow \tan \alpha=1 \\ \\ 45^o\ \textless \ \alpha\ \textless \ 90^o \Rightarrow x\ \textgreater \ y \Rightarrow \frac{x}{y} \ \textgreater \ 1\Rightarrow \tan \alpha\ \textgreater \ 1\)

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